- class property galois.FieldArray.squares : FieldArray
All squares in the finite field.
An element \(x\) in \(\mathrm{GF}(p^m)\) is a square if there exists a \(y\) such that \(y^2 = x\) in the field.
See also
Examples¶
In fields with characteristic 2, every element is a square (with two identical square roots).
In [1]: GF = galois.GF(2**3) In [2]: x = GF.squares; x Out[2]: GF([0, 1, 2, 3, 4, 5, 6, 7], order=2^3) In [3]: y1 = np.sqrt(x); y1 Out[3]: GF([0, 1, 6, 7, 2, 3, 4, 5], order=2^3) In [4]: y2 = -y1; y2 Out[4]: GF([0, 1, 6, 7, 2, 3, 4, 5], order=2^3) In [5]: np.array_equal(y1 ** 2, x) Out[5]: True In [6]: np.array_equal(y2 ** 2, x) Out[6]: True
In [7]: GF = galois.GF(2**3, display="poly") In [8]: x = GF.squares; x Out[8]: GF([ 0, 1, α, α + 1, α^2, α^2 + 1, α^2 + α, α^2 + α + 1], order=2^3) In [9]: y1 = np.sqrt(x); y1 Out[9]: GF([ 0, 1, α^2 + α, α^2 + α + 1, α, α + 1, α^2, α^2 + 1], order=2^3) In [10]: y2 = -y1; y2 Out[10]: GF([ 0, 1, α^2 + α, α^2 + α + 1, α, α + 1, α^2, α^2 + 1], order=2^3) In [11]: np.array_equal(y1 ** 2, x) Out[11]: True In [12]: np.array_equal(y2 ** 2, x) Out[12]: True
In [13]: GF = galois.GF(2**3, display="power") In [14]: x = GF.squares; x Out[14]: GF([ 0, 1, α, α^3, α^2, α^6, α^4, α^5], order=2^3) In [15]: y1 = np.sqrt(x); y1 Out[15]: GF([ 0, 1, α^4, α^5, α, α^3, α^2, α^6], order=2^3) In [16]: y2 = -y1; y2 Out[16]: GF([ 0, 1, α^4, α^5, α, α^3, α^2, α^6], order=2^3) In [17]: np.array_equal(y1 ** 2, x) Out[17]: True In [18]: np.array_equal(y2 ** 2, x) Out[18]: True
In fields with characteristic greater than 2, exactly half of the nonzero elements are squares (with two unique square roots).
In [19]: GF = galois.GF(11) In [20]: x = GF.squares; x Out[20]: GF([0, 1, 3, 4, 5, 9], order=11) In [21]: y1 = np.sqrt(x); y1 Out[21]: GF([0, 1, 5, 2, 4, 3], order=11) In [22]: y2 = -y1; y2 Out[22]: GF([ 0, 10, 6, 9, 7, 8], order=11) In [23]: np.array_equal(y1 ** 2, x) Out[23]: True In [24]: np.array_equal(y2 ** 2, x) Out[24]: True
In [25]: GF = galois.GF(11, display="power") In [26]: x = GF.squares; x Out[26]: GF([ 0, 1, α^8, α^2, α^4, α^6], order=11) In [27]: y1 = np.sqrt(x); y1 Out[27]: GF([ 0, 1, α^4, α, α^2, α^8], order=11) In [28]: y2 = -y1; y2 Out[28]: GF([ 0, α^5, α^9, α^6, α^7, α^3], order=11) In [29]: np.array_equal(y1 ** 2, x) Out[29]: True In [30]: np.array_equal(y2 ** 2, x) Out[30]: True