galois.crt¶
- galois.crt(remainders: Sequence[int], moduli: Sequence[int]) int ¶
- galois.crt(remainders: Sequence[Poly], moduli: Sequence[Poly]) Poly
Solves the simultaneous system of congruences for \(x\).
- Parameters
- Returns
The simultaneous solution \(x\) to the system of congruences.
Notes
This function implements the Chinese Remainder Theorem.
\[\begin{split}x &\equiv a_1\ (\textrm{mod}\ m_1) \\ x &\equiv a_2\ (\textrm{mod}\ m_2) \\ x &\equiv \ldots \\ x &\equiv a_n\ (\textrm{mod}\ m_n)\end{split}\]References
Section 14.5 from https://cacr.uwaterloo.ca/hac/about/chap14.pdf
Examples
Define a system of integer congruences.
In [1]: a = [0, 3, 4] In [2]: m = [3, 4, 5]
Solve the system of congruences.
In [3]: x = galois.crt(a, m); x Out[3]: 39
Show that the solution satisfies each congruence.
In [4]: for i in range(len(a)): ...: ai = x % m[i] ...: print(ai, ai == a[i]) ...: 0 True 3 True 4 True
Define a system of polynomial congruences over \(\mathrm{GF}(7)\).
In [5]: GF = galois.GF(7) In [6]: x_truth = galois.Poly.Random(6, field=GF); x_truth Out[6]: Poly(6x^6 + 5x^5 + 3x^4 + 3x^3 + 4x^2 + 2, GF(7)) In [7]: m = [galois.Poly.Random(3, field=GF), galois.Poly.Random(4, field=GF), galois.Poly.Random(5, field=GF)]; m Out[7]: [Poly(3x^3 + 5x^2 + 2x + 2, GF(7)), Poly(3x^4 + 2x^3 + 6x^2, GF(7)), Poly(4x^5 + 2x^4 + 3x^3 + 6x^2 + x + 1, GF(7))] In [8]: a = [x_truth % mi for mi in m]; a Out[8]: [Poly(3x + 6, GF(7)), Poly(2x^3 + 2, GF(7)), Poly(x^4 + 3x^3 + 3x^2 + 5x + 5, GF(7))]
Solve the system of congruences.
In [9]: x = galois.crt(a, m); x Out[9]: Poly(6x^6 + 5x^5 + 3x^4 + 3x^3 + 4x^2 + 2, GF(7))
Show that the solution satisfies each congruence.
In [10]: for i in range(len(a)): ....: ai = x % m[i] ....: print(ai, ai == a[i]) ....: 3x + 6 True 2x^3 + 2 True x^4 + 3x^3 + 3x^2 + 5x + 5 True
Last update:
May 16, 2022